| Latin Name | Observation date | Location |
|---|---|---|
| Blumea balsamifera | March 17,2025 | Chittagong Division, Bangladesh |
Hi friends how are you all, I hope you are well and I wish you good health. I think it is a great pleasure to observe anything and I observe anything in this community and Google helps me to observe. Today I am sharing a beautiful flower of the natural environment that I saw on the side of the road and the name of this beautiful flower is Erigeron bonariensis flower. I have not observed it properly or deeply whether it is actually a flower or not, but it seems to me to be a very beautiful flower. Because I like it, I enjoy its beauty and take a few pictures with my own mobile.
This is a weed flower and I saw this beautiful flower blooming in a tree on the side of the road. From a distance, I observed this phone and saw that this flower is a little different from other flowers. I saw that this flower has many long petals which I found very delicate to look at. This is a very beautiful and attractive flower to me and I had seen this flower many times on the side of the road before but never shared it with my friends. However, a few days ago I took a picture of this flower and today I am sharing it with everyone. This flower looks very beautiful to me when seen from a distance and I enjoy the beauty of this flower. This flower is not yet in my favorite list and today I saved the name of this flower in my favorite list. Anyway, this is a weed flower. There is so much beauty in the flower that I like and I think the beauty of this flower will be liked by everyone who sees it.
| Camera used | Smartphone |
|---|---|
| Lens | Macro |
| Iso speed | ISO 40 |
| Focal length | 2.13 mm |
| Photography | Blumea balsamifera |
| Location | Chittagong Division, Bangladesh |
| Photographer | @anisurdalim7 |
| Link to original | community |
| Link | https://www.inaturalist.org/observations/269565081 |
| Latitude | Longitude | Map |
|---|---|---|
| 23.58284 | 90.86353 | https://www.openstreetmap.org/#map=18/23.58284/90.86353 |